Let $f(x) = \begin{cases} (x - 1)^{\frac{1}{2 - x}}, & x > 1, x \neq 2 \\ k, & x = 2 \end{cases}$. The value of $k$ for which $f$ is continuous at $x = 2$ is

  • A
    $e^{-2}$
  • B
    $e$
  • C
    $e^{-1}$
  • D
    $1$

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